High Quality for Container Foil Jumbo Roll (Alloy 8011/8006/3003) Export to Greek

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Our development depends on the advanced equipment ,excellent talents and continuously strengthened technology forces for High Quality for Container Foil Jumbo Roll (Alloy 8011/8006/3003) Export to Greek, We are also constantly looking to establish relationship with new suppliers to provide innovative and smart solution to our valued customers.


Aluminum foil jumbo roll for making foil container/foil tray/foil platter, Our container foil jumbo roll is superior household material for packaging which features resistance to water and oil, isolation to light and conductivity of heat. It is environmental friendly and is reusable.

Technical Specifications
♦ Alloy: 8011, 8006, 3003
♦ Temper: Soft (O), H19, H22, H24
♦ Thickness: 0.03-0.15mm
♦ Width: 100-1200mm
♦ Core ID: 76 or 152mm
♦ Coil OD: max 800mm
♦ Roll weight: 100-900kg/roll
♦ Two sides bright

Due to the good character of anti-corrosion,non-poisonous,waterproof,tasteless ,greaseproof and durable. Aluminium foils are widely used in many field ,such as for food industry, pharmaceutical industry,decoration,hairdressing and other sectors. Our factory is a professional manufacturer of aluminium foil products.
We promise high quality, competitive price, fast shipment, best after-service.

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  • Primary :
    U = 230 Volt from the socket. Measured
    I = 1.5 Ampere . Measured
    S = U * I = 230V * 1.5A= 345 VA.
    Z = U / I = 230V / 1.5A = 153 Z ohm (impedance).
    R = 21 R ohm. measured, 1000 turns *2 in parallell. AWG24.
    X = SQRT Z^2 – R^2 = SQRT 153^2 – 21^2 = 151 X ohm (reactance).
    Cos phi = R / Z = 21 R ohm / 153 Z ohm = 0.13 phi
    P = U * I * cos phi = 230V * 1.5A * 1.3 = 44 watt
    R 1000 turns AWG24 = ca 40 ohm .
    It can be calculated that the cosinus phi is considerably low, due to a large self induction in the primary, thus aiding the resistance from the 230V socket, cooling the primary below boiling temprature ! Had the wire been a lone wire with no self inductance the Amperes would probably be about I = U / R = 230V / 21 ohm = 10.9A. The low cosinus phi is a benefit in this case because the turns of the primary can be kept low. Therefore enabling a relatively large ratio between the primary turns and secondary turns. Ratio is about 1000 turns : 50000 turns = 1 : 50 .

    Secondary
    I = 0.05A ??? measured.
    U = maybe 2-3000V (cant measure, destroys the digital meter).
    R secondary coil1 ca 23000 turns awg32 = 6.1 kohm
    R secondary coil2 ca 23000 turns awg32 = 6.1 kohm
    both secondarys in series = 12.2 kohm

    Primary = 1000 turns * 2 in parallell. each coil is 40 ohm
    Ohm primary parallell = 1 / (1/R1 + 1/R1) = 1/( 1/40 ohm + 1/40 ohm ) = 1 / (2/40 ohm )= 20 R ohm.
    I found out that placing the Kirchoff Parallell formula under a 1 fraction, one doesnt have to flip the fraction. Kirchoff parallell = 1 / (1 / R1 + 1/R2 + 1/R3 + n ). find the resistors common multiplum like usual.
    Secondary = 23000 turns * 2.
    Steel cap = 18 Steel plates in 9 layers, each plate is 28.5 * 33.3 cm. Effective area is 0.285m*0.285m * 18 = 1.46 square meter .
    Distance between the plates is ca 3 mm.
    Salt water capacitor bank= 6 jars of glass, Iron bar electrode in salt saturated water, outer plate is aluminium foil, insulated with resin.

    When the spark gap electrodes are of high reactance and not capacitated it seems the discharge is of a yellow thick plasma. Once the coil is capacitated the arc turns blue and white. But I dont know if that is true, for the steel cap produce a long yellow flame .



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